BMI may be easily calculated using the equation provided above or standardized tables. When calculating BMI two intersystem conversions are important: 1 kg = 2.2 lb and 1 m = 39.37 in.
As an example, let us calculate the BMI for a person 5 ft & 1 in in height weighing 120 lb.
BMI = 22.7 kg/m2. This is a normal weight individual according to the guidelines in Appendix 5 (Table A5.1), which shows the classification recommended by both the NIH (National Institutes of Health) and WHO (World Health Organization).
Calculate the BMI values for the following individuals:
Solutions.
CALCULATIONS
ASSESSMENT OF MALNUTRITION
Critical assessment regarding nutritional requirements and adequacy of nutrition support depends on:
Two alternatives are available for nutrition support: enteral nutrition (through a feeding tube placed into the stomach or small bowel) or parenteral nutrition (nutrition solution administered intravenously). Both methods will require initial nutrition assessment to determine the degree of malnutrition and calculations will be needed to determine specific nutrient requirements.
CALCULATION OF NUTRITIONAL REQUIREMENTS
Energy Requirement (Caloric Requirement)
Methods | Description/Equations |
Nomogram | Basal metabolic requirements in function of age, sex, height and body weight |
Indirect calorimetry | Measured estimate of energy utilization |
Ideal body weight (IBW) | IBW rule of thumb or Hamwi equationa: Males IBW = 106 lb (48 kg) + 6 lb (2.7 kg) for each inch (2.54 cm) over 5 ft (152 cm) Females IBW = 100 lb (45 kg) + 5 lb (2.3 kg) for each inch (2.54 cm) over 5 ft (152 cm) TDC = 45 kcal/kg/day × IBWb (kg) |
cHarris–Benedict equation (BEE = basal energy expenditure) | Males BEE (kcal/day) = 66.5 + (13.75 × W(kg)) + (5 × H(cm)) − (6.76 × A(yr)) Females BEE (kcal/day) = 655 + (9.56 × W(kg)) + (1.85 × H(cm)) − (4.68 × A(yr)) TDC = BEE (kcal/day) × 1.25d × stress factore |
Rule of thumb | TDC = 25–35 kcal/kg/day |
General guidelines | Anabolic goal (TDC) = 25 kcal/kg/day (mildly stressed) 30–35 kcal/kg/day (moderately stressed) 45 kcal/kg/day (postoperative) 60 kcal/kg/day (hypercatabolic)f |
a In practice, when the Hamwi equation is used, the resultant weights are rounded to the nearest whole number.
b Usually, the smaller value between IBW (ideal body weight) and ABW (actual body weight) is used for calculation of total daily calorie (TDC) or anabolic goal.
ABW is the patient’s real weight or the patient’s weight at time of consultation. IBW is also known as lean body mass (LBM). An important application of IBW is in the dosing of some drugs that are highly hydrophilic and do not distribute well into fat. For overweight and obese patients, dosing must be based on IBW or the patient will be overdosed.
c The Harris-Benedict equation determines the Basal Metabolic Expenditure (BME), also known as Basal Energy Expenditure (BEE), Resting Metabolic Energy (RME) or Resting Energy Expenditure (REE).
d 1.25 = activity factor (walking, sitting, physical therapy, treatment)
e Stress factor = degree of stress imposed by the disease process and may be:
0.85 = simple starvation, hospitalization
1.05–1.15 = elective surgery
1.20–1.40 = sepsis
1.30 = closed head injury
1.40 = multiple trauma
1.50 = systemic inflammatory response syndrome
2.00 = major burn
f Hypercatabolic states are sepsis, closed head injury, major trauma, and severe burn.
As a general rule, glucose, which is administered daily, is used to provide approximately 60–80% of estimated daily caloric requirement for maintenance of body weight. The remaining caloric requirement is complemented by the infusion of fat emulsion 2–3 times a week.
So Which Method Should I Use to Determine Caloric Requirements?
The patient’s actual body weight in kg is:
Calculation of IBW in kg is:
We will use the smallest body weight (IBW, in this case) for calculation of TDC:
Based on IBW, calculate the total daily calorie requirement for a male patient weighing 198 lb and 5’6” in height.
Solution. 2880 kcal/day
CALCULATIONS
If we consider the patient’s actual body weight, it is 198/2.2 = 90 kg. The usual procedure is to calculate TDC using either ABW or IBW, whichever is smaller.
IBW = 106 lb (48 kg) + 6 lb (2.7 kg) for each inch (2.54 cm) over 5 ft (152 cm)
Solution. 2250 kcal/day
CALCULATIONS
165 cm − 152 cm = 13 cm
IBW = 48 kg + (2.7 kg × 13) = 83.1 kg
Solution. 2043 kcal/day
CALCULATIONS
BEE = 66.5 + (13.75 × W(kg)) + (5 × H(cm)) − (6.76 × A(yr))
BEE = 66.5 + (13.75 × 60) + (5 × 170.2) − (6.76 × 38) = 66.5 + 825 + 851 − 256.9
BEE= 1486 kcal/day
TDC = BEE (kcal/day) × 1.25 × stress factor
TDC = 1486 × 1.25 × 1.10 = 2043 kcal/day
Solution. 2195 kcal/day
CALCULATIONS
BEE = 655 + (9.56 × W(kg)) + (1.85 × H(cm)) − (4.68 × A(yr))
BEE = 665 + (9.56 × 55) + (1.85 × 157.5) − (4.68 × 28) = 665 + 525.8 + 291.4 − 131 = 1351 kcal/day
TDC = BEE (kcal/day) × 1.25 × stress factor
TDC = 1351 × 1.25 × 1.3 = 2195 kcal/day
Solutions.
CALCULATIONS
Solutions. See below.
CALCULATIONS
Using body weight:
158 cm − 152 cm = 6 cm
ABW = 42 kg
IBW = 48 kg + (2.7 kg × 6) = 64.2 kg
Using Harris-Benedict:
BEE = 66.5 + (13.75 × W(kg)) + (5 × H(cm)) − (6.76 × A(yr))
BEE = 66.5 + (13.75 × 42) + (5 × 158) − (6.76 × 32) = 66.5 + 577.5 + 790 − 216.3 = 1218 kcal/day
TDC = BEE (kcal/day) × 1.25 × stress factor
TDC = 1218 × 1.25 × 1.05 = 1599 kcal/day
Using rule of thumb:
These results show that calculations using the Harris-Benedict equation and the rule of thumb produce similar results and seem to be more appropriate than using body weight only because they include a stress factor.
Protein (Nitrogen) Requirement
Patient Status | Daily Requirement Based on Actual Body Weight (g/kg) |
Postoperative (uncomplicated) | 0.8–1.0 |
Postoperative (unable to eat for >10 days) | 1.0–1.5 |
Sepsis and stress | 1.2–1.5 |
Multiple trauma | 1.3–1.7 |
Major burn | 1.8–2.5 |
M.S., 121 lb, will be hospitalized for 2 days after hernia surgery (uncomplicated). What is this patient’s daily amino acid requirement? (Assume a daily requirement of 1 g/kg.)
Solution. 55 g
CALCULATIONS
Solution. 1250 mL
CALCULATIONS
Solution. 540 mL of the 12.5% solution
CALCULATIONS
Since the patient is under fluid restriction, the most concentrated solution must be chosen to allow the smallest volume. Thus,
Micronutrient Requirement
Electrolyte | Requirement (mEq/day) |
Na (sodium) | 80–100 |
K (potassium) | 60–80 |
Mg (magnesium) | 8–16 |
Ca (calcium) | 5–10 |
PO4 (phosphate) | 15–30 |
Cl (chloride) | 50–100 |
Acetate | 50–100 |
Daily multivitamin requirement: 10 mL of standard multivitamin injection. | |
Daily trace elements requirement 1 mL of standard trace elements injection. |
Fluid Requirement
Category | Patient Group | Recommendation |
I | Adults | 35 mL/kg/day |
II | Adults with severe dehydration (e.g., burns over a large part of the body) | 1500 mL (for first 20 kg) + 20 mL/kg/day (for additional kg > 20 kg) |
III | Pediatrics and geriatrics | BW 0–10 kg: 100 mL/kg/day 10 kg < BW < 20 kg: 50 mL/kg/day BW > 20 kg: 20 mL/kg/day |
An 8-year-old child was hospitalized after 4 days with diarrhea and vomiting. At consultation, the child weight was 66 lb. What would be the recommended total daily fluid (TDF) for this patient?
Solution. 600 mL
CALCULATIONS
Considering that the patient is a child, the best approach is to use category III, BW > 20 kg: 20 mL/kg
TDF = 20 mL/kg × 30 kg = 600 mL
Solution.
2100 mL should be used because the patient has major burns and severe dehydration will be present.
CALCULATIONS
Solution. 1500 kcal/day
CALCULATIONS