Smooth Muscle Preparations


The results in Figure 4.1 can be displayed graphically by plotting the log concentration versus response (Figure 4.2).



Figure 4.2 Log concentration–response curves for cholinesters.

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Questions



1. The responses are plotted against the log[cholinester] (M). A series of sigmoid curves with parallel slopes should be obtained.

2. Calculate the ED50 and pD2 values. Also tabulate the maximal responses for each curve.

3. Place the cholinesters in order of relative potency and efficacy.

4. Which of the cholinesters can be termed a full agonist?

4.2.2 Selective Antagonism


Antagonists that selectively bind to receptor types have been pharmacologically useful in many ways, and have been instrumental in defining types of receptors. As the specificity of antagonists binding to different populations of receptors has been identified, the number of sub-types of receptors has grown. The guinea pig ileum contains both cholinergic receptors (M3) and histamine (H1) on the smooth muscle membrane. Nicotinic receptors are present in the neuronal ganglia. The agonists that selectively bind to the receptors used in this experiment are methacholine, histamine and nicotine. Particular care must be taken in using nicotine, to which tachyphylaxis occurs after repetitive dosing. Tachyphylaxis is a form of short-term desensitization of the nicotinic receptor, and can be thought of as a form of protective response. Tachyphylaxis is common with ion channel receptors, and represents a reversion of the channel to an inactive form after prolonged depolarization, with delayed recovery to the resting state. Rapid repeated stimulation of the receptor results in a decrease in response to the same dose. Responses to stimulation of different receptors can be selectively antagonized by atropine (non-selective muscarinic), diphenhydramine (H1) and hexamethonium (neuronal N).


This experiment is designed to demonstrate the following:



1. The presence of cholinergic, histaminergic and nicotinic receptors in the guinea pig ileum. Here acetyl-β-methacholine (methacholine, MCh), histamine and nicotine bitartrate are used as selective agonists of each type of receptor.

2. Contraction produced by these agonists can be selectively antagonized by specific antagonists.

3. Hexamethonium can inhibit responses to nicotine and methacholine, but not histamine. Atropine and diphenhydramine selectively inhibit M (non-selective) and H1 receptors, but neither antagonize responses to nicotine. Thus deductions can be drawn about the anatomical locations of these receptors.

Protocol



1. The guinea pig ileum is set up as detailed above.

2. A partial (four-point) log concentration–response curve is obtained for each agonist. For MCh, a stock solution of 5 × 10−5 M is required. For nicotine, 10−4 M is used. Construct a concentration–response curve for each agonist by adding 0.1 mL, and doubling the volume on subsequent additions until a maximum response is reached. Note that the MCh and nicotine doses must be alternated in order to avoid tachyphylaxis of the responses to nicotine. A contact time of 30 s and cycle time of 90 s should be used throughout these experiments.

3. Select a concentration that is approximately in the middle of each curve (sub-max concentrations). Obtain responses to each of these sub-max concentrations. Add hexamethonium to a bath concentration of 10−6 M.

4. Leave for exactly 1 min and then add the sub-maximal concentration of MCh. Wash out, and add hexamethonium again. After 1 min, add nicotine.

5. Repeat sub-maximal doses of MCh and Nicotine until original responses are restored. This ensures that hexamethonium has been washed out.

6. Now add 0.1 mL of atropine (10−6 M). After 1 min, add the sub-maximal concentration of MCh. Without washing out, add 1 mL of 10 μg/mL MCh.

7. Wash out and replace the atropine.

8. Wash out, replace atropine, wait 1 min, then add nicotine.


Figure 4.3 Typical results obtained for the selective antagonism experiment. (a) Concentration–response curves for methacholine and nicotine. (b) Hexamethonium (10−6 M) inhibited the response to nicotine but did not affect those to methacholine and (c) Atropine (10−6 M) inhibited responses to both methacholine and nicotine.

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Typical results for this experiment are shown in Figure 4.3.


Questions



1. Plot the log concentration–response curves for MCh and nicotine on the same graph (use molar concentrations). What is the reason for using molar concentrations rather than μg/mL? Note the relative potencies.

2. Plot bar graphs of the responses to each of the agonists in the absence and presence of hexamethonium, diphenhydramine and atropine (label with correct bath concentrations).

3. What can you conclude about the specificities of each of the antagonists, and the receptors present in the preparation?

4. Draw a diagram of the suggested location of each of these receptors in the guinea pig ileum.

5. Define the following terms: tachyphylaxis, selective antagonism and competitive antagonism.

4.2.3 Specificity of Blood Cholinesterases


Cholinesterases exist as two isoenzymes: acetylcholine specific cholinesterase (AChE) and the broad specificity butyryl or pseudo-cholinesterase (BuChE or pChE). AChE is bound to the outer post-synaptic membrane and is also found in extraordinarily high concentration within a small portion of the mass of the electroplaques of the organ of the electric eel (Electrophorus electricus). There is also an exceptionally high activity at the neuromuscular junction in the dorsal muscle of the leech (see Section 6.2). pChE has a low specificity and is found in soluble form in blood plasma. It hydrolyses a wide range of cholinesters, and is responsible for the degradation of a number of drugs. An example is the short-term muscle relaxant and depolarizing blocker, succinylcholine, which has a short half-life because it is hydrolysed by pChE. The specificity of these two isoenzymes of cholinesterase can be conveniently demonstrated using blood as a source of both enzymes. AChE is associated with extracellular membrane of red blood cells (RBCs), and, as mentioned, pChE is found in plasma. The specificity of these isoenzymes can be demonstrated by incubating the cholinesters acetylcholine (ACh), methacholine (MCh) and carbachol (CCh) with RBC and plasma and the hydrolysis of the esters monitored by observing the responses of guinea pig isolated ileum. AChE hydrolyses not only ACh, but also pChE. The carbamoyl ester, carbachol, is resistant to hydrolysis by both enzymes.


Protocol



1. Dilute RBC suspension and plasma 1:10 with 0.9% saline. Prepare 20 μM eserine (physostigmine).

2. The isolated GPI is set up in an organ bath aerated with Tyrode’s solution. Concentration–response curves for ACh, MCh, CCh are established as done previously (see Section 4.1.1). A sub-maximal concentration (administered in 0.4 mL or less) is selected from these log concentration–response curves that gives a response on the linear portion of the curve (between 30% and 70% of the maximum response).

3. Label 16 plastic test tubes and pipette the following into each tube (Table 4.1).

4. Incubate the tubes in a water bath at 37°C for 30 min. Remove from water bath and place on ice.

5. Test the response of the ileum to each of these incubated tubes using twice the volume that was used for the selected sub-maximal concentration of cholinester.

Results



6. Plot the log concentration–response curves for each of the cholinesters. Indicate the concentration selected for the incubations.

7. Plot bar graphs of the responses to the contents of each of the tubes.

Table 4.1 Preparation of test-tubes for an experiment to demonstrate the specificity of cholinesterases for cholinesters.


Table04-1


Questions



1. What was the purpose of including tubes 10–14?

2. Describe and explain your results, including the action of eserine.

3. Do RBC, plasma or eserine alone produce a response in the ileum? If so, how do you account for this?

4. What responses would you predict for butyrylcholine (BuCh) alone, BuCh + RBC and BuCh + plasma?

4.2.4 Quantification of the Potency of an Antagonist


This has been introduced in Section 2.1.2. Arunlakshana and Schild (1959) defined a term to describe the potency of an antagonist in terms of the extent to which the antagonist can reduce the potency of an agonist to produce a response. Schild only considered the concentration of the agonist that is required at various antagonist concentrations to produce the same response. He introduced a term pAx, which they defined as the negative log of the concentration of an antagonist that will reduce potency of an antagonist x times. If a tissue is exposed to a competitive antagonist, it will cause a parallel shift of the concentration–response curve to an agonist. The extent to which it shifts the curve is measured by the concentration ratio (CR). This is the concentration of agonist in the presence of antagonist required to produce a fixed response on the linear part of the concentration–response curve divided by the concentration of agonist required to produce the same response in the absence of antagonist. When the antagonist occupies 50% of the receptors, theoretically CR = 2. Schild developed a graphical method to determine a value for −log KB that he termed the pA2 value. The −log value is used to provide a convenient scale for the potency of an antagonist that generally ranges between 5 and 10 (equivalent to concentrations of 10−5–10−10 M). Note that the pA2 value has no units. An experiment is carried out to construct concentration–response curves for an agonist in the absence and presence of at least three concentrations of antagonist. From an equation derived by Gaddum (1937) for the receptor occupancy of an agonist in the presence of a competing, Schild derived an equation relating the CR to KB (the Schild equation):


(4.1) numbered Display Equation


where KB is the equilibrium dissociation constant for the binding of antagonist for the receptor. It is the concentration of antagonist that would occupy 50% of the receptors in the absence of agonist. Theoretically, pKB = pA2


And when expressed as log10,


(4.2) numbered Display Equation


so


(4.3) numbered Display Equation


(which is in the form of y = mx + c).


A graph of log[antagonist], (x), against log(CR − 1), (y), should provide a straight line.


For a competitive antagonist, the slope of the line will be 1, and if the negative log[antagonist] is plotted against log(CR − 1) gives a slope of −1. When CR = 2, the antagonist theoretically occupies 50% of the receptor sites, and so log(1) = 0, so the intercept of the line on the x-axis (−log[antagonist]) = pA2. Note that this analysis is only valid when the slope of the Schild plot = −1. The pA2 value describes the potency of an antagonist (the larger the value, the lower the antagonist concentration, and the more potent is the antagonist). This was an early way of defining or classifying receptors. If an antagonist acts on a receptor with the same pA2 value in different tissues, then the receptors in the two sites are defined as being of the same type. For example, atropine would be expected to give the same pA2 value in any location expressing muscarinic receptors, for example, in ileum, heart or trachea. This value is independent of the agonist used as long as it is acting at the same type of receptor as the antagonist.


Protocol



1. Prepare stock solutions of acetylcholine with concentrations of 1, 10, and 100 μg/mL.

2. Using a 90 s cycle time, construct a concentration–response curve of acetylcholine as in Section 4.2.1.

3. Now add the antagonist, atropine, to the reservoir to produce a bath concentration of 0.1 μg/mL. Empty and fill the organ bath three times to ensure that the atropine solution is in contact with the tissue. It is useful to ensure that this is the case by introducing a small air bubble into the delivery tube, but be careful to maintain the siphon.

4. After 15 min, repeat the concentration–response curve for acetylcholine.

5. Increase the concentration of atropine in the reservoir to 1 μg/mL, and ensure that this solution is in the organ bath, as before. Leave for a further 15 min.

6. Repeat the concentration–response curve for acetylcholine.

7. Repeat this procedure once or twice more, each time increasing the atropine concentration by 10 times.

Analysis



1. Draw the log concentration–response curves for acetylcholine on the same graph.

2. Select a response that falls on the linear part of all the concentration–response curves. Read off the concentrations required to produce this response at each of the concentrations of atropine. These are denoted as C0, C1, C2, etc.

3. The concentration shift ratio (CR) is calculated as C1/C0, C2/C0 etc.

4. Tabulate these values as shown in Table 4.2.

5. Construct a Schild plot by drawing a graph of log(CR − 1) on the abscissa (x-axis) against −log[atropine] on the ordinate (y-axis) as shown in Figure 2.3.

Table 4.2 Used to calculate parameters for a Schild plot.


Table04-1


Questions



1. What is the pA2 value for atropine in this preparation? How is this defined?

2. Is there any evidence to indicate whether atropine is acting competitively at a receptor site in this preparation? If so, which receptor site?

3. Does this agree with values cited in the literature (see Table 2.1)?

4.2.5 Bioassays


A bioassay is designed to estimate the concentration or potency of a compound by measuring its biological response (Rang et al., 2012). Bioassays can be used to measure the concentration of a drug, its potency relative to another drug or its binding constant. Whilst many drugs can be measured by analytical chemical techniques, in many cases the exact structure of the drug is not known, or the activity of the drug may not be reflected by analytical chemical techniques (e.g. peptides, isomers, small molecules). Bioassays may be performed in vivo (in living animals) or in vitro. An essential requirement of a bioassay is the availability of a preparation of the test substance of known standard activity. This is not necessarily a pure preparation. In the cases of many biological substances the activity of an unknown can be compared with that of an international standard, and the results expressed as international units (e.g. hormones or other mediators, clotting factors). There are two different types of bioassays – quantal (all-or-none) bioassays and graded bioassays.


Quantal bioassays are where categorical data are obtained and the response is a non-variable end point, such as LD50 or alive or dead. These are best designed and analysed using a contingency table followed by a χ2 test or Fisher’s exact test (see Section 1.6.2).


Graded bioassays. There are three basic designs of graded, quantitative bioassays which can be used to estimate activity with increasing accuracy.



1. Single-point assays. Here a log dose–response curve for the standard is established, and the response to a single dose of unknown is compared with this curve.

2. Bracketing assays, three-point or 2 × 1 assays. Responses to two doses of the standard are established on the linear part of the sigmoid log dose–response curve. A response to the unknown is found, which is midway between the two standard responses. These are named ‘std1’ (low concentration), ‘std2’ (high concentration) and ‘unk’ (unknown). These responses are brackets. Here, for example, ‘four bracketing’ estimates would have been performed:

image


A typical set of responses are shown in Figure 4.4.

3. Multi-point assays, such as the 4 × 4 assay. These are the most accurate designs of assays. Here as above, two responses to the standard are found that fall on the linear part of the sigmoid dose–response curve (S1 and S2). Two responses to the unknown that also fall in the linear region of the dose–response curve are found (named U1 and U2). These responses are then repeated in a differing order.


Figure 4.4 A record of responses obtained in a bracketing or three-point assay. The data were recorded using Chart software. (ADInstruments Ltd., U.K.)

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Protocol


The guinea pig isolated ileum preparation is set up, as done for the guinea pig isolated ileum preparations described above. Check the maximum response to the standard (add 0.8 mL of 10 μg/mL ACh in the organ bath).


Single-point Assay



1. You are supplied with a standard solution and a stock concentration of the unknown.

2. Add increasing concentration of standard (use 1 μg/mL and 10 μg/mL) to the tissue until you reach the maximal response and you can plot a full log concentration–response curve.

3. Note the linear part of the curve and the approximate 50% of maximum response. Now add volumes of unknown to the organ bath aiming to find a volume (Vunk) that elicits a response on the linear part of the concentration–response curve. You may have to dilute the stock solution of unknown in order to obtain a response that falls on the concentration–response curve for the standard.

4. Read the exact response (Runk) from the curve and find the organ bath concentration of the unknown (Cunk) on the abscissa that corresponds to this response.

So Vunk contains (Cunk × 20) ng of standard (if organ bath volume = 20 mL).


So the concentration of diluted solution of unknown contains:


(4.4) numbered Display Equation


So if the original stock solution of unknown was diluted x times, then the original solution contains (diluted unknown concentration/x) μg/mL.


The design of this assay suffers a great deal of biological variation, and so is inherently inaccurate. This is because the standards and unknown samples were tested over different periods of time. Isolated tissue preparations are notorious for the changes in response over time. The response tends to gradually increase as the tissue recovers from the trauma and changes in temperature occur during the preparation of the tissue. A superior design is the ‘bracketing assay’ as described in the next section.


Bracketing (or three-point) Assay


Select two concentrations of the standard that fall in the linear part of the log concentration–response curve, between 30% and 70% of maximum response to the standard (std1 and std2). Now find a volume of unknown (Vunk) that produces a response approximately midway between these two standard responses (unk). The response to Vunk is bracketed between the responses to std1 and std2. Now repeat these responses in the following order to obtain four overlapping brackets:


numbered Display Equation


A typical record of the results is as shown in Figure 4.4.


Plot the log concentration against response for each of the brackets, and read off the organ bath concentration obtained when Vunk was added (Figure 4.5).



Figure 4.5 Log concentration against response for std1 and std2. The response for the unknown is read off the abscissa to obtain the log of the bath concentration obtained on addition of Vunk.

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Jul 24, 2016 | Posted by in PHARMACY | Comments Off on Smooth Muscle Preparations

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