Write the symbol for the tin isotope with atomic weight 113.

Solution. 113Sn

One way of describing the quantity of a particular radioactive material is through the number of disintegrations that take place in unit time, usually seconds. The reason is that the number of disintegrations is proportional to the amount of material present. The fundamental unit is the Becquerel (Bq), which represents one disintegration per second (dps).

The becquerel is usually too small a unit for practical purposes, so kilo- or megabecquerels are more commonly used.


Solutions.
CALCULATIONS




Solutions.
CALCULATIONS





In this equation, N is the number of radioactive molecules at any time, t, and λ. (lambda) is a rate constant that depends on the identity of the particular substance. Using the notation of differential calculus, the rate of decay can be represented as −dN/dt. This expression describes the change in N with time; the negative sign in front of the expression indicates that as time goes on (increases), N decreases. In the absence of the negative sign, the expression would say that the amount of radioactive substance should grow over time rather than decay.
Which of the following statements are true?

Solution. Both statements are true.


Solution. 0.23 year−1
CALCULATIONS
rate of decay = λN



This equation can be rearranged to

and solved by integration to yield

N0 is defined as the initial number of radioactive atoms present; e is the base of natural logarithms, 2.718. Using this equation and a calculator or log table, it is possible to calculate the amount of radioactivity at any time if we know the original activity and the rate constant.
But before we do any calculations of that type, let us explore some properties of this equation by dividing both sides by N0:

The product of λ and t in this equation has to be dimensionless. Therefore the units of λ are reciprocal time (1/time). For example, if the unit of time used is seconds (s), the units of λ are expressed as 1/s usually written s−1.
Write the units for λ when time is in years.

Solution. 

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